0000006739 00000 n ∆ fus H: Enthalpy of fusion at a given temperature (kJ/mol). 0000005289 00000 n Therefore the given heat change (on the product side) is the enthalpy of combustion in kilocalorie per mole of glucose. << /ID startxref We will do the following steps to solve the problem: Step 1: Calculate the specific heat capacity of the calorimeter. Assume glucose is a 17 0 obj Completing the CAPTCHA proves you are a human and gives you temporary access to the web property. 0000007243 00000 n The bomb calorimeter is commonly used in determining the enthalpy of a substance through combustion reaction using the heat capacity found in the calorimeter and the temperature change released by the reaction. 18 0 obj !>5cgJHtH83];u0KMfendstream 12 0 obj Join thousands of students and gain free access to 46 hours of Chemistry videos that follow the topics your textbook covers. trailer Answer = [–2826 kJ mol–1] **So far I've managed the following: dH = dU + dPV dU = 15.7 kJ P = 1atm endobj << /Outlines 21 0 R /PageMode /UseNone /Pages 18 0 R /Type /Catalog >> The heat capacity of the calorimeter is the quantity of heat required to raise the temperature one degree (6-3) But there are two sources of heat, the burning sample and the burning wire. If the calorimeter contains 875 g {eq}H_2O{/eq} and the bomb has a heat capacity of 457 J/ C, what is the temperature increase of the bomb calorimeter? /Title (D-Galactose Datasheet) >> << /A << /S /URI /Type /Action /URI (http://pubs.acs.org/doi/abs/10.1021/ci990307l) >> /Border [ 0 0 0 ] /Rect [ 144.3629 535.1339 346.1529 547.1339 ] /Subtype /Link /Type /Annot >> Calculate the heat of combustion of glucose at constant volume considering water to be in the gaseous state. xref endobj 4 Fe (s)  +  3 O­2 (g)  → 2 Fe2O3 (s)          The calculated heats of reaction (heats of combustion): Glucose: heat of reaction = [6 x heat of formation of CO 2 (g) + 6 x heat of formation of H 2 O (g)] - [heat of formation of glucose] Heat of reaction = [6 x (-393.5 kJ/mole) + 6 x (-241.8 kJ/mole)] - [-1250 kJ/mole] Become a Study.com member to unlock this endobj << /Annots [ 8 0 R 9 0 R 10 0 R 11 0 R 13 0 R 14 0 R ] /Contents 20 0 R /MediaBox [ 0 0 595.2756 841.8898 ] /Parent 18 0 R /Resources << /Font 1 0 R /ProcSet [ /PDF /Text /ImageB /ImageC /ImageI ] >> /Rotate 0 In ... A: An acidic substance is the substance that can give H+ ions. The specific heat capacity of water is 4.184 J/g K and the molar mass of glucose is 180.2 g/mol. When heated, solid cal... A: Balanced reaction is a chemical reaction in which number of atoms for each element in the reaction a... Q: 6. endobj -ОН 11 0 obj 5 0 obj endobj % ReportLab generated PDF document -- digest (http://www.reportlab.com) << /BitsPerComponent 8 /ColorSpace /DeviceRGB /Filter [ /ASCII85Decode /FlateDecode ] /Height 250 /Length 4683 /Mask [ 250 255 250 255 250 255 ] 18 0 obj % ReportLab generated PDF document -- digest (http://www.reportlab.com) C p,gas: Ideal gas heat capacity (J/mol×K). If the size of the glucose sample had been exactly twice as large, what would the temperature change of the calorimeter have been? Δ f G°: Standard Gibbs free energy of formation (kJ/mol). 12 0 obj b) A 2.500 g sample of glucose was combusted in a bomb 0 22 20 0 obj Δ c H° solid: Standard solid enthalpy of combustion (kJ/mol). 0000007930 00000 n 0000000260 00000 n << /BaseFont /Helvetica-BoldOblique /Encoding /WinAnsiEncoding /Name /F5 /Subtype /Type1 /Type /Font >> 6 0 obj Gau`T>Ar4d'Rl+-s"KM?_k]Y<>;l)59g=h*A9q25VPX/]/5oZC&ZmW]q;7ta0lN_.9@)t)1i0;Q!4NBpS)q0,Jfba"_1!\ml8PW"C-MWEd:ZX(JFjrQd=+\oiiO8m2B\)1fcr3Wq:]p:]5-`f#CqVfsEDq*:-!b]DehCKHOm9/`d@#uWE2+fC;#tQbl:=7XDai\%]bI()Ci$:To`#0mi)dT*@/RNT3Eu+nU\B)WUns,.$4R8VUm@O`r`]mjJlbX!H,=!2ha?`;cWlTs+i;!oIF-'1\@BG;A83f/u'/F7A6!&CR[%1X#H+([^MY3GTEXkd`23]Mjb*m'f'HEU/;f4%(ME_iA@dVKs,3RPFXABG*gD4[\fh:R1OZ8_G+7.%oV.P3_gW-5`ZPXaj/[82H1dsaA\0qif[0YT\T4,XEO;)+J3/'W5:f"K^`AYtaYZsM'V)?em>cY7I(ZUm("-n@gCULV1,+E+@Y(*M@XcQKrRVUm=3ZbF,oX0Xkg'bLMZ8X'eABHQ@"eXZg>PKJf$_+&)f&VL)s+\EgHXr9F/a%*ql1WCGA3E<>Ah2-q^kG;D$BrA^Fe@cl*jgI3"t$)?+!Y?eM1@PDE@-=3B?PO`1)d7dnsC`8t:hu1^TM9g1fIJDdK="C_jt0\.`[6Rh%:@q,u[u@1kWX+EJsIPVDCtU$E=dFOUjbYuQsT6h)X2]&l"2HThVn+Dr$%6GYWOTTL5r,O(Z[=E?,HbdL!TZ+%Io?(fq\i'dq8BG,PMo"CISL\W`b\*N:Zho6,UK;r;._cMN*SlU'Ohch"f9tW$%(&/3STZO"6K>)Mn@lomk.eKp9@rE:^kV:Nfa3tlg)f'FBt^EJAi9#-gL_ZW.dG?d=4J>*8_XSo0Oqt+/]OhWXh0'cfm"E'\[?Fl<>OSC)pJ_2+,*q7\Ur4m`q8_tRJ;+Ac)9.(e*>1q.F. When hydrogen peroxide (H2O2) starts boiling, liquid hydrogen peroxide (H2O2) change in... Q: Im not sure how to do this one. 0000012309 00000 n Earn Transferable Credit & Get your Degree, Get access to this video and our entire Q&A library. endobj c. III Q: Write the formula equation from the word equation. << /A << /S /URI /Type /Action /URI (https://www.chemeo.com/cid/28-751-7/D-Galactose) >> /Border [ 0 0 0 ] /Rect [ 62.69291 186.6555 291.1029 198.6555 ] /Subtype /Link /Type /Annot >> endobj << /Count 2 /Kids [ 7 0 R 15 0 R ] /Type /Pages >> 0000006739 00000 n 0000007930 00000 n 0000000075 00000 n << /Annots [ 8 0 R 9 0 R 10 0 R 11 0 R 13 0 R 14 0 R ] /Contents 20 0 R /MediaBox [ 0 0 595.2756 841.8898 ] /Parent 18 0 R /Resources << /Font 1 0 R /ProcSet [ /PDF /Text /ImageB /ImageC /ImageI ] >> /Rotate 0 Alka-S... Q: In the laboratory, a student adds 57.5 mL of water to 15.1 mL of a 0.508 M nitric acid solution. [(\366\331\273\376\314\\\304\002\023\307}\241\214\344\324\235) (\366\331\273\376\314\\\304\002\023\307}\241\214\344\324\235)] P c: Critical Pressure (kPa). Gau`T>Ar4d'Rl+-s"KM?_k]Y<>;l)59g=h*A9q25VPX/]/5oZC&ZmW]q;7ta0lN_.9@)t)1i0;Q!4NBpS)q0,Jfba"_1!\ml8PW"C-MWEd:ZX(JFjrQd=+\oiiO8m2B\)1fcr3Wq:]p:]5-`f#CqVfsEDq*:-!b]DehCKHOm9/`d@#uWE2+fC;#tQbl:=7XDai\%]bI()Ci$:To`#0mi)dT*@/RNT3Eu+nU\B)WUns,.$4R8VUm@O`r`]mjJlbX!H,=!2ha?`;cWlTs+i;!oIF-'1\@BG;A83f/u'/F7A6!&CR[%1X#H+([^MY3GTEXkd`23]Mjb*m'f'HEU/;f4%(ME_iA@dVKs,3RPFXABG*gD4[\fh:R1OZ8_G+7.%oV.P3_gW-5`ZPXaj/[82H1dsaA\0qif[0YT\T4,XEO;)+J3/'W5:f"K^`AYtaYZsM'V)?em>cY7I(ZUm("-n@gCULV1,+E+@Y(*M@XcQKrRVUm=3ZbF,oX0Xkg'bLMZ8X'eABHQ@"eXZg>PKJf$_+&)f&VL)s+\EgHXr9F/a%*ql1WCGA3E<>Ah2-q^kG;D$BrA^Fe@cl*jgI3"t$)?+!Y?eM1@PDE@-=3B?PO`1)d7dnsC`8t:hu1^TM9g1fIJDdK="C_jt0\.`[6Rh%:@q,u[u@1kWX+EJsIPVDCtU$E=dFOUjbYuQsT6h)X2]&l"2HThVn+Dr$%6GYWOTTL5r,O(Z[=E?,HbdL!TZ+%Io?(fq\i'dq8BG,PMo"CISL\W`b\*N:Zho6,UK;r;._cMN*SlU'Ohch"f9tW$%(&/3STZO"6K>)Mn@lomk.eKp9@rE:^kV:Nfa3tlg)f'FBt^EJAi9#-gL_ZW.dG?d=4J>*8_XSo0Oqt+/]OhWXh0'cfm"E'\[?Fl<>OSC)pJ_2+,*q7\Ur4m`q8_tRJ;+Ac)9.(e*>1q.F.

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